-2x^2=12x=0

Solution for -2x^2=12x=0 equation:

-2x^2=12x=0

We move all terms to the left:

-2x^2-(12x)=0

a = -2; b = -12; c = 0;
Δ = b2-4ac
Δ = -122-4·(-2)·0
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-12}{2*-2}=\frac{0}{-4}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+12}{2*-2}=\frac{24}{-4}
=-6
$